>

### A sample text widget

Etiam pulvinar consectetur dolor sed malesuada. Ut convallis euismod dolor nec pretium. Nunc ut tristique massa.

Nam sodales mi vitae dolor ullamcorper et vulputate enim accumsan. Morbi orci magna, tincidunt vitae molestie nec, molestie at mi. Nulla nulla lorem, suscipit in posuere in, interdum non magna.

Published on August 1st, 2011 In category Education | Maths

Search Similar Topic: , , ;

# How to solve Pipe Cistern problems easily

The pipe and cistern type problems are quite common in competitive exams like CAT, Bank PO etc. I have included some easy way of solving these kind of problems.

Some general rules are as follows:

1. If a pipe attached to reservior or tank can fill in X hours, in 1 hours the tank will filled 1/x

2. If an outlet attached to a tank is opened to empty a tank takes Y hours to flush out till end, in 1 hour the tank wull 1/y part empty

3. If the tank is attached with a pipe that fills it full in X hours and another pipe that empties it full in Y hours then on opening both the pipes togrther the part emptied or full can be determined using Part = (1/x) – (1/y) when Y > X and (1/y) – (1/x) when X>Y

4. If there are 2 pipes ( X, Y)simultaneously filling (emptying) the tank then the part emptied/filled in = (1/x ) + (1/y)

If you liked my contribution, please donate or click on any of advt. a little that will be generated will all be donated for noble cause. [paypal-donation] [ad#Post-Bottom]