Based on the concept we disucussed last time for solving problem related to time, speed and distance. I have included few questions that will help to understand concept of time, distance and speed better. If you need to refer the DST concept please go here.
This quiz is on the topic of the Time, Distance and Speed, each question is of one points and detailed explanation is provided for each question
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Two runner start from the opposite end of the track that is 120 km long at the same time, if first runner runs at the speed of 1o kmph and 2nd runner runs at 20 kmph, after how many minutes they will meet?
Question 1 Explanation:
Please note this is a meeting problem, so the time travelled is same as they start same time and distance travelled is sum of distance travelled which is length of track = 100 Km. For 1st Runner d1 = 10 x t and for 2nd runner d2 = 20 x t add them to equal 120. t = 4 hrs = 240 min
Classical boat problem: A boat takes 6 hours to go up and 4 hours to go down the stream to return to the same point, if the water is flowing at 6 kmph, what would be speed of the boat upstream?
Question 2 Explanation:
Take the speed of the boat as X, as this is a roundtrip problem, the distance travelled by the boat up and down stream is same. The speed of the boat up stream = x - 6 and downstream = x +6. Let distance travelled be y then for upstream y= (x-6) x 6 and downstream y = (x+6) x 4. Calculate the value of x = 30, upstream speed = x -6 = 30 -6 = 24
A news paper delivery van leaves the depo 2 hours late than usual morning time, find the speed it should maintain today so that it can deliver newspaper in time? Today the driver is driving 20 kmph faster and still he will take 3 hours to reach the destination?
Question 3 Explanation:
Create secnarios for 2 days normal and late, this will translate into overtaking problem. So the distance travelled remain same, let us say todays speed when he is late is X, then speed in normal days is X-20. Since he will take another 3 hours to reach distance travelled in late day distance= 3X and a normal day he will take 2 hours late + 3 hours overtake time (X-20) x 5 equate and get the answer X = 50
Ram start 1 hours before Shyam from a highway canteen driving at the speed of 50 kmph , if Shyam is driving at the average speed of 10o kmph in how many hours he will overtake Ram?
will not overtake
Question 4 Explanation:
Since this a problem of overtaking travelling in same directions, distance travelled is same by both cars. Let suppose distance = d, Ram travels d = 50 x (t +1) and Shaym travel d = 100 x t solve for t = 1
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